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Murnaghan

$\displaystyle E(V) = \frac{BV}{B'(B'-1)} \left[ B' \left( 1 - \frac{V_0}{V} \right) + \left( \frac{V_0}{V} \right)^{B'} - 1 \right] + E(V_0)$

(230)

$\displaystyle P(V) = \frac{B}{B'} \left[\left( \frac{V_0}{V} \right)^{B'} - 1\right]$

(231)

ARAI Masao 2003-03-28